语法练习：near_hundred

题目：diff21

Given an int n, return True if it is within 10 of 100 or 200. Note: abs(num) computes the absolute value of a number.

near_hundred(93) → True
near_hundred(90) → True
near_hundred(89) → False

我的解答：

def near_hundred(n):return (abs(n - 100) <= 10) or (abs(n - 200) <= 10)

Expected Run
near_hundred(93) → True True OK
near_hundred(90) → True True OK
near_hundred(89) → False False OK
near_hundred(110) → True True OK
near_hundred(111) → False False OK
near_hundred(121) → False False OK
near_hundred(-101) → False False OK
near_hundred(-209) → False False OK
near_hundred(190) → True True OK
near_hundred(209) → True True OK
near_hundred(0) → False False OK
near_hundred(5) → False False OK
near_hundred(-50) → False False OK
near_hundred(191) → True True OK
near_hundred(189) → False False OK
near_hundred(200) → True True OK
near_hundred(210) → True True OK
near_hundred(211) → False False OK
near_hundred(290) → False False OK

All Correct

标答：

def near_hundred(n):return ((abs(100 - n) <= 10) or (abs(200 - n) <= 10))